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Factoring Trinomials by Grouping

Factoring General Polynomials (grouping number GN)

WHAT TO DO:	HOW TO DO IT:
Example: 6t² + 23t + 20	6t² + 23t + 20
Multiply 6Â· 20:	GN 6Â·20 = 120
Find pairs of integer factors (largest first)
Sign before last term is + so find pair with the SUM of 23	→ 15 + 8 = 23
Both have same sign as middle number + 23	+15, + 8
Rewrite polynomial 6t² + 23t + 20 with 4 terms having correct signs:	6t² + 15t + 8t + 20
Group terms 2 by 2	6t² + 15t + 8t + 20
Factor common term from each group:	3t(2t + 5) + 4(2t + 5)
Note that (2 t + 5) is now common factor and factor it out to get:	(3t + 4)(2t + 5)
Multiply by FOIL to check: Check:
Write out answer: 6t 2 + 23t + 20 = (3t + 4)(2t + 5) or (2t + 5)(3t + 4)