Quadratic Equations
Example
A quadratic equation is expressed in standard form as:
y = 6 Â· x^{ 2} +12 Â· x  90.
Convert this formula to factored form.
Solution
When converting a quadratic function to factored form (or factoring), the
first step is always to factor out by the number that is multiplying x^{ 2}.
In this case that number is 3.
y = 6 Â· (x^{ 2} + 2 Â· x 15).
Next, you look at what is left inside the parentheses. What you are looking
for are two numbers that:
1. Add to give the coefficient of x that still remains inside the
parentheses, and,
2. Multiply to give the constant number that still remains inside the
parentheses.
In this particular example, we are looking for two numbers that will add
to give +2 and that will multiply to give 15. Two numbers that fit this
bill are 3 and +5, as:
3 + 5 = 2
(3)( 15) = 15.
The two numbers 3 and 5 are the numbers that are added to x in each of the
factors of the factored form. As we have already worked out the value of the
constant a (it is 6), the factored form for this quadratic will be:
y = 6 Â· (x + 3) Â· (x + 5) = 6 Â· (x  3) Â· (x + 5) .
Some Common Factoring Patterns
x^{ 2}  a^{ 2} = (x  a) Â· (x + a) â€œDifference of two
squaresâ€
x^{ 2} + 2Â· a Â· x + a^{ 2} = (x + a)^{ 2} â€œPerfect
square Iâ€
x^{ 2}  2 Â· a Â· x + a^{ 2} = (x  a)^{ 2} â€œPerfect
square IIâ€
Example
Convert the quadratic function:
y = 2Â· x^{ 2} 16 Â· x + 42,
from standard to vertex form and locate the x and ycoordinates of the
vertex.
Solution
Once the formula for the quadratic function has been converted to vertex form:
y = a Â· (x  h)^{ 2} + k,
we can find the vertex by checking the vertex form to find the values of h (which
will be the xcoordinate of the vertex) and k (which will be the ycoordinate of
the vertex).
Conversion of the formula from standard to vertex form is a fourstep process
called
completing the square.
1. Factor out the coefficient of x^{ 2} from all terms.
y = 2 Â· (x^{ 2}  8 Â· x + 21)^{ }
2. Add and subtract just the right amount^{* }to create a perfect
square
y = 2 Â· (x^{ 2 } 8 Â· x +16 16 + 21)
3. Factor the perfect square and combine the constants
y = 2Â· ((x  4)^{2} 16 + 21)
y = 2 Â· ((x  4)^{2} + 5)
4. Distribute the factor that is out in front of the equation
y = 2 Â· (x  4)^{2} +10
The vertex form of the quadratic function is:
y = 2 Â· (x  4)^{2} +10.
^{*} To find just the right amount, you take the number that is left
multiplying the x after Step 1 has been completed. Whatever this number is,
divide the number by 2 and then take the square of what you are left with. This
is just the right amount to create a perfect square.
