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= AB + AC + AD + ...
= A(C + D) + B(C + D)
= AC + AD + BC + BD
= 2x + 2·3
= 2x + 6
= 3x·x + 3x·(-1)
= 3x2 - 3x
= (- 5)(x2) + (- 5)(2x) + (- 5)(- 3)
= - 5x2 - 10x + 15
= x(y + b) + a(y + b)
= xy + xb + ay + ab
With practice we can do the second line in our head and go directly to the third line.
= x (2x + 3) + 2(2x + 3)
= x·2x + x·3 + 2·2x + 2·3
= 2x2 + 3x + 4x + 6
= 2x2 + 7x + 6
Later, skip this second line and →
go directly to this third line. →
= 2x·2x + 2x·3 + 3·2x + 3·3
= 4x2 + 6x + 6x + 9
= 4x2 + 12x + 9
Note the “equal and opposites†→
cancel out here.
= 2x·2x + 2x·(- 3) + 3·2x + 3·(- 3)
= 4x2 - 6x + 6x - 9
= 4x2 - 9